Your are subscriber and logged in!
Basic Maths Tools
Before we learn about techniques to solve the ray-triangle intersection test, let's first look at some of the tools we will be using to solve this problem. As we said earlier, the triangle's vertices define a plane. Every plane has a normal which can be seen as a line perpendicular to the plane's surface. Considering that we know the coordinates of the triangles vertices (A, B and C), we can compute the vectors AB and AC (which are simply the lines going from A to B and A to C). To do so, we simply subtract B from A and C from A.
To compute the normal of the plane (which, logically, is the same as the triangle's normal since the triangle lies in the plane) we simply compute the cross product of AB and AC. Remember, these two vectors lie in the same plane since they connect the triangle's vertices. The vector resulting from this cross product (denoted N) is the normal we are looking for (figure 1). These operations are summarized in this pseudocode example:
If we normalize C we get the vector (0, 0, 1) which as you can see, is parallel to the positive z-axis which is what we expect since the vertices v0, v1 and v2 lie in the xy-plane.
Coordinate System Handedness
The order in which a triangles' vertices are defined affects the orientation of the surface's normal. V0, V1, and V2, created in a counter-clockwise order (CCW), produce a normal denoted N. If the vertices are created in a clockwise order (CW), the normal which we compute from the cross product of the two edges (A=V1-V0 and B=V2-V0) would then point in the opposite direction to the first computed N.
When you create a triangle in Maya (which is using a right-hand coordinate system), if you turn CCW as you create the triangle's vertices, then the x-axis (V0V1) becomes A, the y-axis (V0V2) becomes B and C, the cross product AxB, is parallel to the z-axis (figure 2). But if create vertices in clockwise order, then C will point along the negative z-axis (creating vertices in CW order and computing N from the cross product AxB is the same as computing the cross product BxA when the vertices are created in CCW with A=V1-V0 and B=V2-V0).
Now imagine that you create this triangle in a left-hand coordinate system from three vertices which have exactly the same coordinates than in the right-hand coordinate system example (V0 = (0,0,0), V1=(1,0,0) and V2=(0,1,0)). Following the same steps, we can create the vector A (V1-V0) and B (V2-V0) and compute C (from AxB). The result is also equal to (0,0,1) as with the right-hand coordinate system example (the vertices coordinates are the same, therefore the vectors A and B are the same as well as the result of the cross product AxB). Remember though, that by convention, the z-axis in the left-hand coordinate system is pointing in the direction of the screen (when the x-axis is pointing to the right). Again, everything is coherent with the explanations we have given so far about the handedness of coordinate systems. The result of the cross product as we mentioned in lesson on Geometry, is an anti-commutative operation.
Now the next step is to render each one of these triangles from a camera which is pointing down the negative z-axis. The result of these tests are shown in figure 4. The two resulting images don't look the same even though the triangle's vertices have exactly the same coordinates, which is not what we want. The choice of a coordinate system's handedness should not change the way geometry is seen from the camera's point of view. A person rendering an image probably wants to see the same image of the same triangle independently from the handedness being used. Even though this is not directly related to the topic of ray-triangle intersection test, this is an important problem which you need to know about. Usually the way we solve it is by mirroring the camera along the negative z-axis (both its position and orientation) as shown in figure 4.
This is working however you can see that now the direction of the camera and the direction of the normal have changed compared to what we had before mirroring the camera. In figure 3, the camera's direction and the triangle's normal are pointing in opposite directions. But in figure 4, they are now pointing in the same direction. These two vectors (the triangle's normal and the camera direction) play an important role in shading and it is therefore important that we do not change their direction in relation to each other. Therefore the solution to the problem of the flipped triangle is not only to mirror the camera but also to flip the normal direction. Remember though that this is only necessary if you modelled the triangle in a modeling application using a left-hand coordinate system but render it in a renderer using a right-hand coordinate system (or vice-versa which is the case if you generate geometry in Maya and render this geometry in RenderMan which is using a right- and left-hand coordinate system respectively).
The combination of order and direction in which the vertices are specified is called winding.
We now have all the tools at hand to solve the ray-triangle intersection test using simple geometry.